Math Games

[Tikobe]

(Also not known as "Me procrastinating on my work")

Game 1:

What are three operations you can do to the number 2 that allows 2 to avoid being a number in the 20's? You can't use specific scenarios using other numbers such as (Multiply 2 by 100) but you can use somewhat narrower versions of general scenarios such as (Multiply 2 by a number in the hundreds) or situations like (Find the squareroot of 2) since they don't use other numbers. You also cannot use the examples I've provided or scenarios that someone else has chosen. You also can't do something such as (Multiply 2 by a number in the hundreds) and follow that with (Multiply 2 by a number in the two hundreds) or do something like that when another person has used (Multiply 2 by a number in the hundreds), but you can follow the first one with something like (Multiply 2 by a number in the thousands). However, with those examples being said, lets not do too many multiplications like those.

I'll start. Loser is the first person who is unable to provide three answers, breaks a rule or comes out with an incorrect answer.

1. Find the reciprocal of 2.
2. Find the absolute value of 2.
3. Make 2 equal the value of x.

[Bannanachair]

(Also not known as "Tikobe procrastinating on replying to Everwake". I'm kidding, you have that research paper, but also, I want to see what's happening at the Shrine.)

(Also, finding the squareroot of 2 involves the number 1/2, because √2=2^(1/2))

1. Multiply 2 by the imaginary number i
2. Multiply 2 by a number n where n≤1
3. Add 2 to itself.

[Tikobe]

(How'd you do that square root sign? Asking so I can edit that into my status)

1. Find the natural log of 2

2. Use to 2 to subtract from a number in the negatives

3. Set the diameter of a circle to 2.

[Tikobe]

Nov 5, 2018 8:12:08 GMT -4 Bannanachair said:

(Also not known as "Tikobe procrastinating on replying to Everwake". I'm kidding, you have that research paper, but also, I want to see what's happening at the Shrine.)

(Also, finding the squareroot of 2 involves the number 1/2, because √2=2^(1/2))

1. Multiply 2 by the imaginary number i
2. Multiply 2 by a number n where n≤1
3. Add 2 to itself.

(Also, should mention that I don't count squareroot in spite of  the 2^(1/2) scenario since squarerooting is a basic enough function that I'm willing to show some leniency in that scenario)